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[求助]ARCGIS中配准时坐标怎么算???
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<TR> <TD vAlign=top width=* height="100%"><IMG src="http://www.gisempire.com/bbs/Skins/Default/topicface/face1.gif" align=absMiddle border=0> <B>[求助]ARCGIS中配准时坐标怎么算???</B><BR> <P>手头有扫描图需要配准,在arcgis里配准的时候,要输入X、Y坐标,请问这个坐标是什么坐标?怎么算?另外,在扫描图上有已有经纬度的四个角点,这些点又是什么?当采用仿射(AFFINE)的方法时,坐标点怎么算?</P> <P>如图层信息是:In projected or local coodinates</P> <P> Left -0.010000 Right 67.542373</P> <P> Top 97.370674 Bottom 0.000000</P> <P><U><STRONG><FONT color=#ee6911>事先得知该图幅的对应经纬度范围为<FONT face="Times New Roman">99.023293</FONT>~<FONT face="Times New Roman">148.031029</FONT>°<FONT face="Times New Roman">E</FONT>,<FONT face="Times New Roman">-9.939420</FONT>~<FONT face="Times New Roman">53.060567</FONT>°<FONT face="Times New Roman">N</FONT></FONT></STRONG></U><U><STRONG><FONT color=#ee6911>,(</FONT><FONT color=#000000>怎样知道???)</FONT></STRONG></U>由此可推算出如下四个用于校正的控制点: <br> <p> <P align=center><V:RECT></V:RECT><FONT face="Times New Roman">1 0.000000 0.000000 99.023293 -9.939420 <p></FONT> <p> <P align=center><FONT face="Times New Roman">2 67.541534 0.000000 148.031029 -9.939420 <p></FONT> <p> <P align=center><FONT face="Times New Roman">3 67.541534 97.370674 148.031029 53.060567 <p></FONT> <p> <P align=center><FONT face="Times New Roman">4 0.000000 97.370674 99.023293 53.060567</FONT></P> <P align=center><FONT face="Times New Roman"> <p></FONT> <p> <P> <P>上述点怎么确定呢???? </P> <P>我是新手,可能这问题对大家来说太简单了,呵呵。敬请解答,谢谢!</P></TD></TR></TABLE> |
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2楼#
发布于:2007-05-31 22:35
同问
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3楼#
发布于:2007-06-05 19:09
<P>期待高手来指点一下~~~~</P>
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4楼#
发布于:2007-06-05 21:50
用看图软件读出你的扫描图的四个角的公里网格交叉点的坐标,然后用ARCMAP配准。
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