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阅读:1585回复:7
[原创]关于CenterAt
<P>我想做一个列表,列出所有的对象,当选择一个对象时,地图会放大到以该点为中心的区域。</P>
<P>这里必须用到centerat,可是centerat x,y中的xy点需要已知。请问如果不已知怎么办???</P> <P>谢谢各位</P><img src="images/post/smile/dvbbs/em02.gif" /><img src="images/post/smile/dvbbs/em02.gif" /><img src="images/post/smile/dvbbs/em02.gif" /> |
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1楼#
发布于:2005-04-04 16:14
<P>看看下面这个帖子,可以让你放大到选择的对象,这里不管是点,线面,通吃,:)</P><P><a href="http://www.gisempire.com/bbs/dispbbs.asp?BoardID=39;ID=4432" target="_blank" >http://www.gisempire.com/bbs/dispbbs.asp?BoardID=39;ID=4432</A></P>
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2楼#
发布于:2005-04-01 19:41
解决了 。 别忘了事先定义一下对象
Set shp_points = New MapObjects2.Points Set shp_points = shape_line.Parts(0) Dim i As Integer For i = 0 To shp_points.Count - 1 List1.AddItem shp_points.Item(i).x Next i Set shp_pt1 = New MapObjects2.Point Set shp_pt2 = New MapObjects2.Point Set shp_pt1 = shp_points.Item(0) Set shp_pt2 = shp_points.Item(shp_points.Count - 1) Dim ptx1 As Single, pty1 As Single, ptx2 As Single, pty2 As Single ptx1 = shp_pt1.x pty1 = shp_pt1.y ptx2 = shp_pt2.x pty2 = shp_pt2.y Dim ptx As Single, pty As Single ptx = (ptx1 + ptx2) / 2 pty = (pty1 + pty2) / 2 Map1.CenterAt ptx, pty End If<img src="images/post/smile/dvbbs/em01.gif" /><img src="images/post/smile/dvbbs/em01.gif" /><img src="images/post/smile/dvbbs/em01.gif" /> |
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3楼#
发布于:2005-02-22 15:10
<img src="images/post/smile/dvbbs/em02.gif" /><img src="images/post/smile/dvbbs/em02.gif" /><img src="images/post/smile/dvbbs/em02.gif" /> |
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4楼#
发布于:2005-02-22 08:54
对,楼上说的不错!
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5楼#
发布于:2005-02-21 08:28
点和多边形图层可以做到,线形图层如何做????
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6楼#
发布于:2005-02-21 08:14
试试去。谢谢!!<img src="images/post/smile/dvbbs/em02.gif" /><img src="images/post/smile/dvbbs/em02.gif" /><img src="images/post/smile/dvbbs/em02.gif" />
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7楼#
发布于:2005-02-19 10:23
<P>获取对象的extent,赋值给一个rectangle对象,再将rectangle对象的center赋给point对象就OK了</P>
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